A Question about rear axel shims

[46HARLEY]

Originally Posted by nkaminar

The amount that the shim moves the hub out is equal to the thickness of the shim divided by the tangent of half the angle of the taper. I don't know what the angle of the taper is, but for example lets say it is 7 degrees. A 0.005 thick shim would then move the hub out 0.082 inch. 0.005/Tangent(7/2)

This also applies to any wear in the hub or axle. With the same taper 0.005 wear would move the hub, and drum, IN 0.082 inch.

Thanks for the math, that looks about what the axel nut moved compared to the cotter pin hole. Larry