Quote:
Originally Posted by frnkeore
S&B,
I saw that in the PDF but, if you look at my addition of the crank throw, rod and CH, it adds up to 10.503. That would put the piston .065 out of the block.
The CH I use, is the replacement piston, that TRW made in 1978, L912F.
So, something isn't right.
Frank
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It all depends on the stroke - the piston you're using has a different or wrong CH. If I modify my CAD model to use a different crankshaft stroke, then the CH has to change in order for the piston to be zero-decked. The end deck height remains the same.
Note: Their dimension for 'Comp Dist' is wrong - here are the basic numbers for the different strokes - which are easy to calculate - just add/subtract from the numbers in my drawing (based on 1/2 the stroke change/difference):
3.750 = 1.561
4.000 = 1.436
4.125 = 1.374 (what my drawing shows - as that is the crank I'm using)
4.250 = 1.311
PS: The drawing is correct - the math works out and matches the 'stocking' pistons that Ross and others supply. What is your math?