A question for those with a Laycock unit already installed: how is the solenoid wired?
It comes from a 12 volt negative ground, and I don't currently see a way to isolate it from ground. Which would imply that the 12 volt negative ground circuit would have to coexist along 6 volt positive ground - sharing the ground.
My understanding of physics says it probably can work out this way, but reality might disprove it.
Any comments or thoughts on this would be appreciated
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